y' = -2/(sinx - cosx)^2 Start by taking a look at your function y = (sinx + cosx)/(sinx - cosx) Notice that this function is actually the quotient of two other functions, let's call them f(x) and g(x) {(f(x) = sinx + cosx), (g(x) = sinx - cosx) :} This means that you can differentiate this function by using the quotient rule, which allows you to find the derivative of a function that's the
Thered line is cos(x), the blue is the approximation (try plotting it yourself) : 1 − x 2 /2! divided by all the exponents so far multiplied together (for which we can use factorial notation, Try that for sin(x) yourself, it will help you to learn.
ExperiencedPhysics Teacher for Physics Tutoring. See tutors like this. Kenneth gave you a good answer. Here is another way, using the identity. sinθ = cos (π/2 - θ) and the property. cos (-x) = cos (x). Let θ = x + π/2. Then.
Wecan also define the tangent of the angle as its sine divided by its cosine: tan To find this answer on the unit circle, we start by finding the sin and cos values as the y-coordinate and x-coordinate, respectively: sin 30° = 1/2 and cos 30° = √3/2. Now use the formula. Recall that tan 30° = sin 30° / cos 30° =
Areabetween two curves given end points. Google Classroom. You might need: Calculator. The curves f (x)=\sin x f (x) = sinx and g (x)=\cos x g(x) = cosx intersect periodically. Determine the area of the region bounded by these curves between x=\dfrac {\pi} {4} x = 4π and x=\dfrac {5\pi} {4} x = 45π.
CommonMisconceptions. >. Memorization tricks. >. Click a picture with our app and get instant verified solutions. Click here👆to get an answer to your question ️ intdx/sin^2 xcos^2x equals.
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what is cos x divided by sin x
